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In this article, a fuzzy Elzaki transform (FZT) is discussed in the context of highlygeneralized differentiability concepts, where a new formula of fuzzy derivatives for the fuzzy Elzaki transform is derived as well. It shows the applicability of this interesting fuzzy transform for solving differential equations with constant coefficients also for its computational power. Since ordinary linear equations are mostly used in physical fields, the motion of a mass on a vibrating spring problem is solved by using this kind of fuzzy Elzaki transform.
fuzzy Elzaki transform, Sumudu transform, the motion of a mass, vibrating spring equation
There is no doubt that most mathematical equations, including multiple variables or constant coefficients, and their derivatives deal with reallife phenomena. Various aspects of physics, engineering, and biology have been adapted to common differential equations, which are indicators of the crucial role of partial differential equations in modeling problems. [1] Analytical and numerical methods have been utilized by numerous researchers to solve common differential equations [2, 3]. Even so, these equations (ODEs) are limited to dealing with some important cases, such as the modeling of a certain dynamic phenomenon using (ODEs) where it is not always accurate. In addition to inadequate data and understanding of the dynamic system, fuzziness in the initial values may provide an explanation for this.
On the other hand, in operational calculations that use solving (ODEs), integral transforms constitute critical tools and can be useful. It seems that integrated transformations convert the original complicated function into an easiertoresolve new function. In this regard, the Fourier transform can consider as the first integral transform then followed by Laplace, Mellin, and wavelet transform [4]. Fuzzy transforms such as Laplace and Sumudu were then applied to solve ordinary linear fuzzy differential equation [57]. Indeed, fuzzy transform not just solve (ODEs) but also fractional nonlinear partial differential equations, fractional ordinary differential equations, and system of linear partial or ordinary differential equations [811]. Fuzzy transform was proposed as a pilot fuzzy approximation approach to applying in unusual application fields such as numerical solutions of (ODEs) [12].
Bulut et al. [13] employed the Sumudu transform to solve nonhomogeneous fractional ordinary differential equations. The findings showed the fact that the Sumudu transform can be employed to solve many problems of applied sciences. Yang and Hou [14] proofed that The Laplace decomposition method is a precise technique to deal with both linear and nonlinear fractional integrodifferential equations. In the same regard, Mohammed [15] presented numerical examples and used the leastsquares method to solve linear fractional integrodifferential equations.
Jena and Chakraverty [16] introduced a hybrid technique to solve the Navier–Stokes equation. The findings showed that the proposed method is accurate, successful, and simple to use for various science and engineeringrelated issues. Verma and Alam [17] presented some of the examples in the electric circuit and proved that the technique of Elzaki transform was very strong in simultaneous differential equations. In the same regard, Suleman et al. [18] compared Elzaki 's transform with other conventional methods and found it to be versatile and has flexible efficiency. Ziane et al. [19] evaluated Elzaki 's transition to solve nonlinear partial differential equations with timefractional derivative and reported that the technique quite successful for such problems. Singh and Sharma [20] argued that the transformation of Elzaki and its properties could be attributed to the transformation of Laplace. They employed the technique on nonlinear homogeneous and nonhomogenous fractional and showed that methodologies suggested solving this kind of complex equation were effective, simple, and highly accurate. Ige et al. [21] combined the Elzaki transform method and Adomian polynomials to solve KleinGordon equations. The results are consistent with the results of previous studies regarding the accuracy and efficiency of the Elzaki transform. Khalouta and Kadem [22] employed a mixed Elzaki transform and the projected differential transformation method and reported that the technique was reliable compared to the traditional techniques.
Lately, to solve the linear system, Tarig M. Elzaki and Salih M. Elzaki produced a new integral transformation, it was Elzaki transform [23], which then used by Tarig [24] to solve common differential equations with more details. For the same purpose, Adam [25] conducted a comparative investigation between two methods, i.e. Adomain Decomposition and Elzaki Transform, and reported that both techniques were powerful and efficient. Khalid et al. [26] employed Elzaki transform to solve nonhomogeneous fractional by using Matlab and MathWork.
Note that, the concept of derivative proposed by Bede and Gal [27] is based on the Hukuhara difference that cocalled by "generalized Hukuhara differentiability”. Moreover, the existence and uniqueness of a “solution of fuzzy initial value” problem in higherorder using the “classical form of Hukuhara differentiability has been” represented by Georgiou et al. [28]. The motion of a mass on a vibrating spring, which represents a real problem which solving by this new technique.
In this article, instate dealing with classical kinds of (ODEs), we submit a new method for solving (FODEs) using (FZT). The current manuscript is partition as shown below: Section 1, here we review some of the fundamental definitions of the concept of a fuzzy number. Section 2, we represented fuzzy Elzaki transform definition (FZT) beside some related theorems and their proofs. Section 3, the connection between fuzzy Sumudu transform (FST) and (FZT) is discussed by theorems concerning the (FZT) to solve (ODEs). Section 4, as a reallife problem, the motion of a mass on a spring is discussed as an application for fuzzy Elzaki transform.
2.1 Fuzzy number [3]
A fuzzy number $\psi$ in parametric form is a pair $(\underline{\psi}, \bar{\psi})$ of functions $\underline{\psi}(\eta), \bar{\psi}(\eta), 0 \leq \eta \leq 1,$ that meets the requirements as follows:
1 $\underline{\psi}(\eta)$ is a bounded nondecreasing left continuous function in (0,1] while right continuous at 0.
2 $\bar{\psi}(\eta)$ is a bounded nonincreasing left continuous function in (0,1], and right continuous at 0.
3 $\underline{\psi}(\eta) \leq \bar{\psi}(\eta), 0 \leq \eta \leq 1$.
2.2 Operations of fuzzy number [3]
Let $\psi=(\underline{\psi}(\eta), \bar{\psi}(\eta)), 0 \leq \eta \leq 1$ and $\theta=(\underline{\theta}(\eta), \bar{\theta}(\eta))$, $\eta>0$ be an arbitrary constant, we can realize addition $\psi \oplus \theta$ subtraction $\psi \ominus \theta$ and scalar multiplication by $\propto$ as:
(a) Addition: $\psi \oplus \theta=(\underline{\psi}(\eta)+\underline{\theta}(\eta), \bar{\psi}(\eta)+\bar{\theta}(\eta))$
(b) Subtraction $\psi \ominus \theta=(\underline{\psi}(\eta)\underline{\theta}(\eta), \bar{\psi}(\eta)\bar{\theta}(\eta))$
(c) Scalar multiplication $\propto \odot \psi=\left\{\begin{array}{l}(\propto \underline{\psi}, \alpha \bar{\psi}) \propto \geq 0 \\ (\propto \bar{\psi}, \alpha \underline{\psi}) \propto<0\end{array}\right\}$
2.3 Fuzzy values for functions of the first derivative [29]
Let $\xi: R \rightarrow E$ be a function and denote $\xi(\tau)=$ $(\underline \xi(\tau ; \eta), \bar{\xi}(\tau ; \eta))$ for each $r \in[0,1]$ Then
1If $\xi$ is no.1, then $\xi(\tau ; \eta)$ and $\bar{\xi}(\tau ; \eta)$ are differentiable functions and $\xi^{\prime}(\tau)=(\underline\xi(\tau ; \eta), \bar{\xi}(\tau ; \eta))$.
2If $\xi$ is no.2, then $\underline\xi(\tau ; \eta)$ and $\bar{\xi}(\tau ; \eta)$ are differentiable functions and $\xi^{\prime}(\tau)=(\bar{\xi}(\tau ; \eta), \underline\xi(\tau ; \eta))$.
2.4 Fuzzy values for functions of the nth derivatives [30]:
Suppose that $\beta(\tau), \beta^{\prime}(\tau), \ldots, \beta^{n1}(\tau)$ are differential fuzzy valued functions such that $\beta^{(i 1)}(\tau), \beta^{(i 2)}(\tau), \ldots, \beta^{(i m)}(\tau)$ are no.2 functions for $0 \leq i_{1}<i_{2}<i_{3}<\ldots<i_{m} \leq n1$ and $\beta^{p}(\tau)$ is no.1 for $p \neq i_{j}, j=1,2,3, \ldots, m$ and if $\eta$ cut representation of fuzzy $$ value function $\beta(\tau)$ is denoted by $\beta(\tau)=(\underline{\beta}(\tau, \eta), \bar{\beta}(\tau, \eta)),$ then:
a. If $m$ is an E.N, then $\beta^{(n)}(\tau)=\left(\underline{\beta}^{(n)}(\tau, \eta), \bar{\beta}^{(n)}(\tau, \eta)\right)$.
b. If $m$ is an O.N, then $\quad \beta^{(n)}(\tau)=\left(\bar{\beta}^{(n)}(\tau, \eta), \underline{\beta}^{(n)}(\tau, \eta)\right)$.
2.5 Fuzzy Sumudu transform for fuzzy nth derivatives [31, 32]
Suppose the $\beta(\tau), \beta^{\prime}(\tau), \ldots, \beta^{n1}(\tau)$ are continuous fuzzyvalue function on $[0, \infty)$ and of exponential order that $\beta^{n}(\tau)$ is piecewise continuous fuzzy valued function on $[0, \infty)$. Let $\beta^{(i 1)}(\tau), \beta^{(i 2)}(\tau), \ldots, \beta^{(i m)}(\tau)$ are no. 2 function for $0 \leq i_{1}<$ $i_{2}<i_{3}<\ldots<i_{m} \leq n1$ and $\beta^{p}(\tau)$ is no.1 function $p \neq$ $i_{j}, j=1,2,3, \ldots, m$ and, $\beta(\tau)=(\beta(\tau, \eta), \bar{\beta}(\tau, \eta)),$ then
1. If $m$ is an E.N, we have $S\left[\beta^{n}(\tau)\right]=\frac{\psi(u)}{u^{n}} \ominus \frac{\beta(0)}{u^{n}} \otimes$ $\sum_{k=1}^{n1} \frac{1}{u^{nk}} \beta^{k}(0)$.
Such that
$\otimes=\left\{\begin{array}{l}\ominus \text { If the no. } 2 \text { functions } \beta^{i}(\tau), \text { provided } i<k \text { is } 0 . \mathrm{N} \\ \text { If the no. } 2 \text { functions } \beta^{i}(\tau), \text { provided } i<k \text { is E. } \mathrm{N}\end{array}\right.$
2. If m is an O.N, we have
$S\left[\beta^{n}(\tau)\right]=\frac{\beta(0)}{u^{n}} \ominus\left(\frac{\Psi(u)}{u^{n}}\right) \otimes \sum_{k=1}^{n1} \frac{1}{u^{nk}} \beta^{k}(0)$
Such that
$\otimes=\left\{\begin{array}{l}\ominus \text { If the no. } 2 \text { functions } \beta^{i}(\tau), \text { provided } i<k \text { is } 0 . \mathrm{N} \\ \text { If the no. } 2 \text { functions } \beta^{i}(\tau), \text { provided } i<k \text { is E. } \mathrm{N}\end{array}\right.$
3.1 Fuzzy Elzaki transform
let $\psi: R \rightarrow E(R)$ be continuous fuzzy valued function, consider that $u^{2} \psi(u \tau) e^{\tau} d \tau$ is improper fuzzy Riemannintegral on $[0, \infty),$ then $u^{2} \int_{0}^{\infty} \psi(u \tau) e^{\tau} d \tau$ is named fuzzy Elzaki transform which is define by $\Phi(u)=E[\psi(\tau)]=$ $u^{2} \int_{0}^{\infty} \psi(u \tau) e^{\tau} d \tau, k_{1}<u<k_{2},$ then we get:
$u^{2} \int_{0}^{\infty} \psi(u \tau) e^{\tau} d \tau=$ $\left[u^{2} \int_{0}^{\infty} \underline{\psi}(u \tau) e^{\tau} d \tau, u^{2} \int_{0}^{\infty} \bar{\psi}(u \tau) e^{\tau} d \tau\right],$ by classical $\mathrm{Elzaki}$ transform, we have:
$e[\underline{\psi}(\tau, \eta)]=u^{2} \int_{0}^{\infty} \underline{\psi}(u \tau) e^{\tau} d \tau$,
$e[\bar{\psi}(\tau, \eta)]=u^{2} \int_{0}^{\infty} \bar{\psi}(u \tau) e^{\tau} d \tau$.
Finally, we get: $E[\psi(\tau)]=(e[\underline{\psi}(\tau ; \eta)], e[\bar{\psi}(\tau ; \eta)])$.
3.2 Linear property
Let $\psi, \theta: \Re \rightarrow E(\Re)$ be two continuous fuzzy functions, assume that $b_{1}$ and $b_{2}$ random constants, after that:
$E\left[\left(b_{1} \quad \odot \psi(\tau)\right) \oplus\left(b_{2} \odot \theta(\tau)\right)\right]=\left(b_{1} \quad \odot E(\psi(\tau)) \oplus\right.$$\left(b_{2} \odot E(\theta(\tau))\right.$
Proof: $\quad$ let $\quad \psi(\tau)=(\underline{\psi}(\tau ; \eta), \bar{\psi}(\tau ; \eta)), \theta(\tau)=$ $(\underline{\theta}(\tau ; \eta), \bar{\theta}(\tau ; \eta))$
Form definition (3.1), we obtain
$e\left(\left[b_{1} \underline{\psi}(\tau)\right]+\left[b_{2} \underline{\theta}(\tau)\right]\right)$
$=u^{2} \int_{0}^{\infty} b_{1} \underline{\psi}(u \tau) e^{\tau} d \tau$
$+u^{2} \int_{0}^{\infty} b_{2} \underline{\theta}(u \tau) e^{\tau} d \tau$
$=b_{1} \int_{0}^{\infty} u^{2} \underline{\psi}(u \tau) e^{\tau} d \tau$
$+b_{2} \int_{0}^{\infty} u^{2} \underline{\theta}(u \tau) e^{\tau} d \tau$
$=b_{1} e[\underline{\psi}(\tau)]+b_{2} e[\underline{\theta}(\tau)]$
And
$e\left(\left\lceil b_{1} \bar{\psi}(\tau)\right]+\left[b_{2} \bar{\theta}(\tau)\right]\right)$
$=u^{2} \int_{0}^{\infty} b_{1} \bar{\psi}(u \tau) e^{\tau} d \tau$
$+u^{2} \int_{0}^{\infty} b_{2} \bar{\theta}(u \tau) e^{\tau} d \tau$
$=b_{1} \int_{0}^{\infty} u^{2} \bar{\psi}(u \tau) e^{\tau} d \tau$
$+b_{2} \int_{0}^{\infty} u^{2} \bar{\theta}(u \tau) e^{\tau} d \tau$
$=b_{1} e[\bar{\psi}(\tau)]+b_{2} e[\bar{\theta}(\tau)]$
Thus,
$\left(b_{1} \odot E(\psi(\tau)) \oplus\left(b_{2} \odot E(\theta(\tau))\right.\right.$.
3.3 Change of scale property
Consider $\psi: \Re \rightarrow E(\Re)$ be a continuous fuzzy function and $b$ is a random constant then, $E[\psi(b \tau)]=\Phi(b \tau)$.
Proof: We have:
$\psi(\tau)=(\underline{\psi}(b \tau ; \alpha), \bar{\psi}(b \tau ; \alpha))=(e[\underline{\psi}(b \tau ; \alpha)], e[\bar{\psi}(b \tau ; \alpha)])$
$=\left(u^{2} \int_{0}^{\infty} \underline{\psi}(b u \tau, \alpha) d \tau, u^{2} \int_{0}^{\infty} \bar{\psi}(b u \tau, \alpha) d \tau\right)=\Phi(b \tau)$
4.1 Connection between fuzzy Sumudu and Elzaki transforms
Let $\psi(\tau)$ be a continuous fuzzy  value function, if $\Psi(u)$ is a fuzzy the Sumudu of $\psi(\tau)$ and $\Phi(u)$ is the fuzzy Elzaki transform of $\psi(\tau)$ then $\Phi(u)=u^{2} \Psi(u)$
Proof: let $\psi(\tau) \in E(\Re)$ then $u \in k_{1}, k_{2} .$ Form definition (3.1), we get
$\begin{aligned} \Phi(u)=E[\psi(\tau)] &=\left(\begin{array}{c}u^{2} \int_{0}^{\infty} \frac{\psi(u \tau, \eta) e^{\tau} d \tau}{} \\ u^{2} \int_{0}^{\infty} \bar{\psi}(u \tau, \eta) e^{\tau} d \tau\end{array}\right), \Phi(u) \\=u^{2} &\left(\begin{array}{l}\int_{0}^{\infty} \frac{\psi(u \tau, \eta) e^{\tau} d \tau}{\psi} \\ \int_{0}^{\infty} \bar{\psi}(u \tau, \eta) e^{\tau} d \tau\end{array}\right) \Phi(u)=u^{2} \Psi(u) \end{aligned}$
4.2 The first derivative to fuzzy Elzaki transform
Let $\psi: R \rightarrow E(R)$ be continuous fuzzy value function and $\psi$ is the primitive of $\psi^{\prime}$ on $[0, \infty),$ and
1. If $\psi(\tau)$ is no.1, $E\left[\psi^{\prime}(\tau)\right]=\frac{\Phi(u)}{u} \ominus u \psi(0)$.
2. If $\psi(\tau)$ is no.2, $E\left[\psi^{\prime}(\tau)\right]=u \psi(0) \ominus\left(\frac{\Phi(u)}{u}\right)$.
Proof: $(1),$ since $\psi(\tau)$ is no. $1,$ then by theorem $(2.1 .4)(\mathrm{a})$ we get:
$\psi^{\prime}(\tau)=\left(\underline{\psi^{\prime}}(\tau), \overline{\psi^{\prime}}(\tau)\right)$
Therefore, we obtain
$E\left[\psi^{\prime}(\tau)\right]=E\left(\underline{\psi}^{\prime}(\tau), \bar{\psi}^{\prime}(\tau)\right)=\left(e\left[\underline{\psi}^{\prime}(\tau)\right], e\left[\bar{\psi}^{\prime}(\tau)\right]\right)$.
From Elzaki transform, we get
$e\left[\overline{\psi^{\prime}}(\tau)\right]=\frac{\Phi(u)}{u}u \bar{\psi}(0)$
$e\left[\underline{\psi^{\prime}}(\tau)\right]=\frac{\Phi(u)}{u}u \underline{\psi}(0)$ (1)
Since $\psi(\tau)$ is no.1, then by theorem (2.4) (a) we get,
$\psi(0)=(\underline{\psi}(0, \alpha), \bar{\psi}(0, \alpha))$,
then the Eq. (1) become
$E\left[\psi^{\prime}(\tau)\right]=\left(\frac{e[\underline{\psi}(\tau, \alpha]}{u}u \underline{\psi}(0, \alpha), \frac{e[\bar{\psi}(\tau, \alpha]}{u}u \bar{\psi}(0, \alpha)\right)$ $=\frac{\Phi(u)}{u} \ominus u \psi(0)$
Now to prove (2), since $\psi(\tau)$ is no.2, then by theorem (2.4) (b), we get:
$\psi^{\prime}(\tau)=\left(\overline{\psi^{\prime}}(\tau), \underline{\psi^{\prime}}(\tau)\right)$
Therefore, we obtain
$\left.E\left[\psi^{\prime}(\tau)\right]=E\left(\overline{\psi^{\prime}}(\tau), \underline{\psi}^{\prime}(\tau)\right)=(e [\underline{\psi} ^{\prime}(\tau)], e\left[\bar{\psi}^{\prime}(\tau)\right]\right)$.
From Elzaki transform, we get
$e\left[\overline{\psi^{\prime}}(\tau)\right]=\frac{\Phi(u)}{u}u \bar{\psi}(0)$
$e\left[\underline{\psi}^{\prime}(\tau)\right]=\frac{\Phi(u)}{u}u \underline{\psi}(0)$ (2)
Since $\psi(\tau)$ is no.2, then by theorem (2.4) (b) we get, $\psi(0)=(\bar{\psi}(0, \alpha), \underline{\psi}(0, \alpha))$, then the Eq. (1) become
$\left.E\left[\psi^{\prime}(\tau)\right]=\left(\frac{e[\underline{\psi}(\tau, \alpha]}{u}u \underline{\psi}(0, \alpha), \frac{e[\bar{\psi}(\tau, \alpha]}{u}u \bar{\psi}(0, \alpha)\right)\right)$ $=u \psi(0) \ominus\left(\frac{\Phi(u)}{u}\right)$
4.3 The second derivative to fuzzy Elzaki transform
let $\psi(\tau)$ and $\psi^{\prime}(\tau)$ are continuous fuzzyvalue function on $[0, \infty)$ and $\psi^{\prime \prime}(\tau)$ is the piecewise continuous fuzzy $$ valued function on $[0, \infty),$ then
1. If $\psi(\tau)$ and $\psi^{\prime}(\tau)$ no.2, then $E\left[\psi^{\prime \prime}(\tau)\right]=\frac{\Phi(u)}{u} \ominus \psi(0) \ominus$ $u \psi^{\prime}(0)$
2. If $\psi(\tau)$ is no.1 and $\psi^{\prime}(\tau)$ is no.2, then $E\left[\psi^{\prime \prime}(\tau)\right]=$ $\psi(0) \ominus\left(\frac{\Phi(u)}{u}\right)u \psi^{\prime}(0)$
3. If $\psi^{\prime}(\tau)$ is no.1 and $\psi(\tau)$ is no.2, then $E\left[\psi^{\prime \prime}(\tau)\right]=$ $\psi(0) \ominus\left(\frac{\Phi(u)}{u}\right) \theta u \psi^{\prime}(0)$
4. If $\psi(\tau)$ and $\psi^{\prime}(\tau)$ are no.1, then $E\left[\psi^{\prime \prime}(\tau)\right]=\frac{\Phi(u)}{u} \ominus$ $u \psi(0)\psi^{\prime}(0)$
Proof: we prove (2); since $\psi(\tau)$ is no.1 and $\psi^{\prime}(\tau)$ is no.2, then by theorem (2.5) (b), we get
$\psi^{\prime \prime}(\tau)=\left[\overline{\psi^{\prime \prime}}(\tau), \underline{\psi^{\prime \prime}}(\tau)\right]$
where,
$E\left[\psi^{\prime}(\tau)\right]=E\left[\overline{\psi^{\prime \prime}}(\tau), \underline{\psi^{\prime \prime}}(\tau)\right]=\left(e\left[\overline{\psi^{\prime \prime}}(\tau)\right], e\left[\underline{\psi^{\prime \prime}}(\tau)\right]\right)$
From the Elzaki transform, we get
$e\left(\overline{\psi^{\prime \prime}}(\tau, \eta)=\frac{e[\bar{\psi}(\tau, \alpha]}{u}\bar{\psi}(0)u \bar{\psi}^{\prime}(0)\right.$
$e\left(\underline{\psi^{\prime \prime}}(\tau, \eta)=\frac{e[\underline{\psi}(\tau, \alpha]}{u}\underline{\psi}(0)u \underline{\psi}^{\prime}(0)\right.$ (3)
Since $\psi(\tau)$ is no.1 and $\psi^{\prime}(\tau)$ is no.2, then by theorem (2.4) (a) we get
$\psi(0)=\lceil\underline{\psi}(0, \eta), \bar{\psi}(0, \eta)], \psi^{\prime}(0)=\left\lceil\overline{\psi^{\prime}}(0, \eta), \underline{\psi}^{\prime}(0, \eta)\right]$
then the Eq. (3) become
$E\left[\psi^{\prime \prime}(\tau)\right]=\left[\frac{e[\bar{\psi}(\tau, \alpha]}{u}\bar{\psi}(0)u \bar{\psi}^{\prime}(0), \frac{e[\underline{\psi}(\tau, \alpha]}{u}\underline{\psi}(0)\right.$
$\left.u \underline{\psi}^{\prime}(0)\right] E\left[\psi^{\prime \prime}(\tau)\right]$$=\psi(0) \ominus\left(\frac{\Phi(u)}{u}\right)u \psi^{\prime}(0)$
4.4 Fuzzy Elzaki transform for fuzzy nth derivatives
Suppose that $\psi(\tau), \psi^{\prime}(\tau), \ldots, \psi^{n1}(\tau)$ are continuous fuzzy value function on $[0, \infty)$ and of exponential order that $\psi^{n}(\tau)$ is piecewise continuous fuzzy valued function on $[0, \infty) .$ Let $\psi^{i_{1}}(\tau), \psi^{i_{2}}(\tau), \ldots, \psi^{i_{m}}(\tau)$ are no.2 function for $0 \leq i_{1}<i_{2}<i_{3}<\ldots<i_{m} \leq n1 \quad$ and $\quad \psi^{p}(\tau) \quad$ is no.1 function $p \neq i_{j}, j=1,2,3, \ldots, m, \psi(\tau)=(\underline{\psi}(\tau, \eta), \bar{\psi}(\tau, \eta))$ and 1If $m$ is an E.N, we have $\Phi_{n}(u)=\left\lceil\frac{E[\psi(\tau)]}{u^{n}} \ominus \frac{\psi(0)}{u^{n2}} \otimes \sum_{k=1}^{n1} \frac{1}{u^{nk2}} \psi^{k}(0)\right]$
Such that
$\otimes=\left\{\begin{array}{l}\ominus \text { If the no. } 2 \text { functions } \psi^{l}(\tau), \text { provided } l<k \text { is } 0 . \mathrm{N} \\ \text { If the no. } 2 \text { functions } \psi^{i}(\tau), \text { provided } i<k \text { is } \mathrm{E.N}\end{array}\right.$
2If $m$ is $\mathrm{O}. \mathrm{N},$ we have $\Phi_{n}(u)=\left[\frac{\psi(0)}{u^{n2}} \ominus\left(\frac{E[\psi(\tau)]}{u^{n}}\right) \otimes \sum_{k=1}^{n1} \frac{1}{u^{nk2}} \psi^{k}(0) \mid \right]$ Such that
$\otimes=\left\{\begin{array}{l}\ominus \text { If the no. } 2 \text { functions } \psi^{l}(\tau), \text { provided } l<k \text { is } 0 . \mathrm{N} \\ \text { If the no. } 2 \text { functions } \psi^{i}(\tau), \text { provided } i<k \text { is E. } \mathrm{N}\end{array}\right.$
Proof: we can proof as in the preceding theorem, but by the duality relationship between Sumudu and Elzaki, suppose that: $\Phi_{n}(u)=E[\psi(\tau)], \Psi_{n}(u)=S[\psi(\tau)]$.
From Thorem (4.1), we have
$\Phi_{n}(u)=u^{2} \Psi_{n}(u)$ (4)
1 If m is E.N, then from theorem (2.5), Eq. (4) become
$\Phi_{n}(u)=u^{2}\left[\frac{S[\psi(\tau)]}{u^{n}} \ominus \frac{\psi(0)}{u^{n}} \otimes \sum_{k=1}^{n1} \frac{1}{u^{nk}} \psi^{k}(0)\right]$
$\Phi_{n}(u)=\left[\frac{1}{u^{n}}\left(u^{2} S[\psi(\tau)]\right) \ominus \frac{\psi(0)}{u^{n2}} \otimes \sum_{k=1}^{n1} \frac{1}{u^{nk2}} \psi^{k}(0)\right]$
$\Phi_{n}(u)=\left[\frac{E[\psi(\tau)]}{u^{n}} \ominus \frac{\psi(0)}{u^{n2}} \otimes \sum_{k=1}^{n1} \frac{1}{u^{nk2}} \psi^{k}(0)\right]$
2 If m is O.N, then from theorem (2.5), Eq. (4) become:
$\boldsymbol{\Phi}_{n}(\boldsymbol{u})=\boldsymbol{u}^{2}\left[\frac{\boldsymbol{\psi}(\boldsymbol{0})}{\boldsymbol{u}^{n}} \ominus\left(\frac{\boldsymbol{S}[\boldsymbol{\psi}(\boldsymbol{\tau})]}{\boldsymbol{u}^{n}}\right) \otimes \sum_{k=1}^{n1} \frac{\boldsymbol{1}}{\boldsymbol{u}^{nk}} \boldsymbol{\psi}^{k}(\boldsymbol{0})\right]$
$\Phi_{n}(u)=\left[\frac{\psi(0)}{u^{n2}} \ominus \frac{1}{u^{n}}\left(u^{2} S[\psi(\tau)]\right) \otimes \sum_{k=1}^{n1} \frac{1}{u^{nk2}} \psi^{k}(0)\right]$
$\Phi_{n}(u)=\left[\frac{\psi(0)}{u^{n2}} \theta\left(\frac{E[\psi(\tau)]}{u^{n}}\right) \otimes \sum_{k=1}^{n1} \frac{1}{u^{nk2}} \psi^{k}(0)\right]$
There are numerous physical problems that have same mathematical model. Thus, there are many mathematical methods to solve these problems. As a reallife problem, the motion of a mass on a spring which is represented in the following example as an application for fuzzy Elzaki transform in solving problems of “initial value” described by ordinary differential equations.
It is known that the change in the length of the spring is proportional to the force acting its length, so the ideal spring is that when no have a mass. A mass is a hard body whose acceleration according to the Newton’s second law.
Example
Consider the vibrating mass in Figure $1,$ then spring constant is $\beta^{2}$, there is no forcing function and damping force is $A \sin \omega t,$ the differential equation of motion:
$\Omega^{\prime \prime}(\tau)+\beta^{2} \Omega(\tau)=A \sin \omega t, \Omega(0)=\left(X_{0}\alpha, \alphaX_{0}\right)$,
$\Omega^{\prime}(0)=\left(V_{0}\alpha, \alphaV_{0}\right)$
Figure 1. Vibration of a spring
By fuzzy Elzaki transform method we have $E\left[\Omega^{\prime \prime}(\tau)\right]\beta^{2} E[\Omega(\tau)]=A E[\sin \omega t]$.
Case 1: If $\Omega(\tau)$ and $\Omega^{\prime}(\tau)$ are no. $2,$ then
$\begin{aligned} e[\underline{\Omega}(\tau)]=&\left(X_{0}\alpha\right) \frac{u^{2}}{1+\beta^{2} u^{2}}+\left(V_{0}\alpha\right) \frac{u^{3}}{1+\beta^{2} u^{2}}+\\ & \frac{A \omega}{\omega^{2}\beta^{2}}\left[\frac{u^{3}}{1+\omega^{2} u^{2}}+\frac{u^{2}}{1+\beta^{2} u^{2}}\right] \end{aligned}$
$\begin{aligned} E[\underline{\Omega}(\tau)] &=\left(X_{0}\alpha\right) \cos \beta t+\frac{\left(V_{0}\alpha\right)}{\beta} \sin \beta t+\\ & \frac{A}{\omega^{2}\beta^{2}}\left(\sin \omega t\frac{\omega}{\beta} \sin \beta t\right) \end{aligned}$
$e[\bar{\Omega}(\tau)]=\left(\alphaX_{0}\right) \frac{u^{2}}{1+\beta^{2} u^{2}}+\left(\alphaV_{0}\right) \frac{u^{3}}{1+\beta^{2} u^{2}}+$
$\frac{A \omega}{\omega^{2}\beta^{2}}\left[\frac{u^{3}}{1+\omega^{2} u^{2}}+\frac{u^{2}}{1+\beta^{2} u^{2}}\right]$
$E[\bar{\Omega}(\tau)]=\left(\alphaX_{0}\right) \cos \beta t+\frac{\left(\alphaV_{0}\right)}{\beta} \sin \beta t+$
$\frac{A}{\omega^{2}\beta^{2}}\left(\sin \omega t\frac{\omega}{\beta} \sin \beta t\right)$
Figure 2 shows the graph of this case.
Case 2: if $\Omega(\tau)$ is no. 1 and $\Omega^{\prime}(\tau)$ is no.2, then
$\begin{aligned} e[\underline{\Omega}(\tau)]=&\left(X_{0}\alpha\right) \frac{u^{2}}{1\beta^{2} u^{2}}\left(V_{0}\alpha\right) \frac{u^{3}}{1\beta^{2} u^{2}}+\\ & \frac{A \omega}{\omega^{2}\beta^{2}}\left[\frac{u^{3}}{1+\omega^{2} u^{2}}+\frac{u^{2}}{1+\beta^{2} u^{2}}\right] \end{aligned}$
$\begin{aligned} E[\underline{\Omega}(\tau)]=&\left(X_{0}\alpha\right) \cosh \beta t\frac{\left(V_{0}\alpha\right)}{\beta} \sinh \beta t+\\ & \frac{A}{\omega^{2}\beta^{2}}\left(\sin \omega t\frac{\omega}{\beta} \sin \beta t\right) \end{aligned}$
$\begin{aligned} e[\bar{\Omega}(\tau)]=&\left(\alphaX_{0}\right) \frac{u^{2}}{1\beta^{2} u^{2}}\left(\alphaV_{0}\right) \frac{u^{3}}{1\beta^{2} u^{2}}+\\ & \frac{A \omega}{\omega^{2}\beta^{2}}\left[\frac{u^{3}}{1+\omega^{2} u^{2}}+\frac{u^{2}}{1+\beta^{2} u^{2}}\right] \end{aligned}$
$\begin{aligned} E[\bar{\Omega}(\tau)]=\left(\alphaX_{0}\right) \cosh \beta t\frac{\left(\alphaV_{0}\right)}{\beta} \sinh \beta t+ & \frac{A}{\omega^{2}\beta^{2}}\left(\sin \omega t\frac{\omega}{\beta} \sin \beta t\right) \end{aligned}$
Figure 3 shows the graph of this case.
Figure 2. Case (1)
Figure 3. Case (2)
Case 3 : if $\Omega^{\prime}(\tau)$ be no. 1 and $\Omega(\tau)$ is no. 2 , then
$e[\underline \Omega(\tau)]=\left(X_{0}\alpha\right) \frac{u^{2}}{1\beta^{2} u^{2}}+\left(V_{0}\alpha\right) \frac{u^{3}}{1\beta^{2} u^{2}}+$$\frac{A \omega}{\omega^{2}\beta^{2}}\left[\frac{u^{3}}{1+\omega^{2} u^{2}}+\frac{u^{2}}{1+\beta^{2} u^{2}}\right]$
$E[\underline\Omega(\tau)]=\left(X_{0}\alpha\right) \cosh \beta t+\frac{\left(V_{0}\alpha\right)}{\beta} \sinh \beta t+$$\frac{A}{\omega^{2}\beta^{2}}\left(\sin \omega t\frac{\omega}{\beta} \sin \beta t\right)$
$\begin{aligned} e[\bar{\Omega}(\tau)]=\left(\alphaX_{0}\right) \frac{u^{2}}{1\beta^{2} u^{2}}+\left(\alphaV_{0}\right) \frac{u^{3}}{1\beta^{2} u^{2}}+ & \frac{A \omega}{\omega^{2}\beta^{2}}\left[\frac{u^{3}}{1+\omega^{2} u^{2}}+\frac{u^{2}}{1+\beta^{2} u^{2}}\right] \end{aligned}$
$\begin{aligned} E[\bar{\Omega}(\tau)]=\left(\alphaX_{0}\right) \cosh \beta t+\frac{\left(\alphaV_{0}\right)}{\beta} \sinh \beta t+& \frac{A}{\omega^{2}\beta^{2}}\left(\sin \omega t\frac{\omega}{\beta} \sin \beta t\right) \end{aligned}$
Figure 4 shows the graph of this case.
Case 4: If $\Omega(\tau)$ and $\Omega^{\prime}(\tau)$ are no. $1,$ then
$\begin{aligned} e[\underline\Omega(\tau)]=\left(X_{0}\alpha\right) \frac{u^{2}}{1+\beta^{2} u^{2}}\left(V_{0}\alpha\right) \frac{u^{3}}{1+\beta^{2} u^{2}}+ & \frac{A \omega}{\omega^{2}\beta^{2}}\left[\frac{u^{3}}{1+\omega^{2} u^{2}}+\frac{u^{2}}{1+\beta^{2} u^{2}}\right] \end{aligned}$
$\begin{aligned} E[\underline\Omega(\tau)] &=\left(X_{0}\alpha\right) \cos \beta t\frac{\left(V_{0}\alpha\right)}{\beta} \sin \beta t+\\ & \frac{A}{\omega^{2}\beta^{2}}\left(\sin \omega t\frac{\omega}{\beta} \sin \beta t\right) \end{aligned}$
$\begin{aligned} e[\bar{\Omega}(\tau)]=&\left(\alphaX_{0}\right) \frac{u^{2}}{1+\beta^{2} u^{2}}\left(\alphaV_{0}\right) \frac{u^{3}}{1+\beta^{2} u^{2}}+\\ & \frac{A \omega}{\omega^{2}\beta^{2}}\left[\frac{u^{3}}{1+\omega^{2} u^{2}}+\frac{u^{2}}{1+\beta^{2} u^{2}}\right] \end{aligned}$
$\begin{aligned} E[\bar{\Omega}(\tau)] &=\left(\alphaX_{0}\right) \cos \beta t\frac{\left(\alphaV_{0}\right)}{\beta} \sin \beta t+\\ & \frac{A}{\omega^{2}\beta^{2}}\left(\sin \omega t\frac{\omega}{\beta} \sin \beta t\right) \end{aligned}$
Figure 5 shows the graph of this case.
Figure 4. Case (3)
Figure 5. Case (4)
The solution of an initial value problem addresses several physical problems. The procedure demonstrates that many physical problems that have the same mathematical model in addition to a fundamental relationship between physics and mathematics. There are many different forces acting upon the mass on a spring, the force is positive if it acts in the downward direction whereas the force will be negative if it acts in the upward direction. Therefore, this paper considered the mass motion of the spring in a few specifics as the first step in the investigation of more complex vibrational systems is the understanding of the behavior of this basic mechanism.
O.N 
odd number 
E.N 
Even number 
no.1 
(i)differentiable 
no.2 
(ii)differentiabl 
E 
Elzaki transform 
S 
Sumudu transform 
Greek symbols 

$\oplus$ 
fuzzy addition 
$\ominus$ 
fuzzy Subtraction 
$\beta^{2}$ 
spring constant 
$A \sin \omega t$ 
damping force 
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